DaveS
1
I doubt I will EVER get my head wrapped around how to craft a proper RegEx statement.
Here is what I need to do
- Trim trailing whitespace from WITHIN a block of text…
This is a test ^
of an example ^
piece of text ^
where ^ if EOL
would become
This is a test^
of an example^
piece of text^
and it should also accomodate the text ending in whitespace but no trailing EOL
in Addition I need another RegEx to trim LEADING white space in a similar manner
DaveS
2
I tried this
[^ \t\r\n])[ \t]+$"
but worked, but also removed the last non whitespace character
Hi Dave - Try this one to see if this what you are looking for:
(?-U)(?!(\w))\s+(?=\B)
HTH
Mike
DaveS
4
It didn’t work
s=s.replacingOccurrences(of: "(?-U)(?!(\\w))\\s+(?=\\B)", with: "", options: .regularExpression)
note : Swift does required the \ be doubled up (escape )
FYI… This works for removing LEADING whitespace
s=s.replacingOccurrences(of: "^\\s+" , with: "", options: .regularExpression)
s=s.replacingOccurrences(of: "\\n\\s+", with: "\n", options: .regularExpression)
1 Like
pidog
5
How about
s=s.replacingOccurrences(of: "\\s+$" , with: "", options: .regularExpression)
s=s.replacingOccurrences(of: "\\s+\\n", with: "\n", options: .regularExpression)
DaveS
6
Strange… I swear I had tried exactly that earlier… but it did work… thanks